Don't you think it could be better if we can remove users that haven't been active in 6 months?
1) More space for more awesome stuff
2) Frees up names that are popular (Like Mario, Pikachu, Samus, etc)
3) If I were admin, I wouldn't want users to have an account if they only intend to visit for one day.
So who's with me?
Suggestion: Removing Inactive Users?
Started by StreetPassWanter, Nov 26 2011 08:17 PM
2 replies to this topic
#2
Posted 26 November 2011 - 08:38 PM
There is little purpose in removing old members.
1) This is not an issue. 10 MB is enough for roughly 20,000 posts, give or take 3,000. And accounts take up even less space than posts do. As far as server space goes, trust me when I say it's not an issue.
2) If anyone wants the username of an inactive account, they are free to contact me. We do this on MLP Forums, and it has worked well so far.
3) Inactive members have still gone through the registration process, which involves providing a valid email address. I can send mass emails out to all members, which can potentially bring them back, advertise a Wii U pre-order link, or otherwise get their attention. I plan to send out a couple of such emails around the holidays, and I can guarantee that the more people receive them, the more effective they'll be.
1) This is not an issue. 10 MB is enough for roughly 20,000 posts, give or take 3,000. And accounts take up even less space than posts do. As far as server space goes, trust me when I say it's not an issue.
2) If anyone wants the username of an inactive account, they are free to contact me. We do this on MLP Forums, and it has worked well so far.
3) Inactive members have still gone through the registration process, which involves providing a valid email address. I can send mass emails out to all members, which can potentially bring them back, advertise a Wii U pre-order link, or otherwise get their attention. I plan to send out a couple of such emails around the holidays, and I can guarantee that the more people receive them, the more effective they'll be.
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